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Collision course

Discussion in 'The Tanks of World War 2' started by PanzerMeister, Feb 12, 2005.

  1. Roel

    Roel New Member

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    I was about to say "maybe a better engineer..." ;)
     
  2. Ome_Joop

    Ome_Joop New Member

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    Actually when bove objects (not necesserilly same weight) collide with each other head on they both bounce back or atleast the force....like those metallic balls on a wire that bounce back when they hit each other!!!
    Remember this law: Action = Reaction!

    The Formula for Kinetic Energy is still: Ek =0.5 x m x (v x v)
    Ek= kinetic Energy
    m = mass
    v = velocity in meter per second

    back to the tank traveling at 60Km/u (60/3,6 = 16,667 m/s):
    Ek = 0.5 x 68700 x (16,667 x 16,667) = J
    Ek = 34350 x 277,778 =
    Ek = 9541666,667 J

    So something went wrong with the calculation....
     
  3. Ome_Joop

    Ome_Joop New Member

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    BTW this means that when a tank would drive twice as fast 120 km/u the Kinetic energy would be 4 times as high!!!

    120 / 3,6 = 33,333

    Ek = 0.5 x 68700 x (33,333 x 33,333) = J
    Ek = 34350 x 1111,111 =
    Ek = 38166666,666 J

    This is 4 times as much!!!

    38166666,666 J / 9541666,667 J = 4

    Back to topic...

    1 tank hitting a stationary tank at 60kp/u will have an Ek of 9541666,667 J

    2 tanks driving 60 hitting each other head on will have each have an Ek of 60km/u 9541666,667 J and will do theoratically 2 times as much damage.... 9541666,667 J + 9541666,667 J = 19083333,334 J
     
  4. Jeffrey phpbb3

    Jeffrey phpbb3 New Member

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    OMG, this topic gets me confused... :kill:

    Lets just say wen they hit eachother at 60km/h the crew is probably badly injured, as a tankdriver you can even hurt your whole crew by max. braking, the tank will stop in its own lenght, and it has happen before, tankcrews even ended up in hospital because of this kind of jokes...
     
  5. Christian Ankerstjerne

    Christian Ankerstjerne Member

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    Ome_Joop
    No, because the speeds aren't added up.

    Christian
     
  6. Ome_Joop

    Ome_Joop New Member

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    You are right Christian I Think i made a mistake somewhere!

    Ek total of tanks colliding head on whould have an Ek double that of a tank driving 60Km/H!
    refrase the formula for that a bit!

    Ek total = (Ek tank1) + (Ek tank2)

    Ek total = (9541666,667) + (- 9541666,667)

    Ek total = 0

    Total Kinetic Energy would be however in this case be 0 as they are heading into each other......

    Need to study some more?! it's been a while!
     
  7. TiffanyAyala

    TiffanyAyala New Member

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    Oh, very interesting. I didn't read it before. I and my friend like it and we would like to reread it and follow your upgrade.
     
  8. lwd

    lwd Ace

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    I don't think so. For one thing energy isn't a vector. So the KE of tank one doesn't cancel out the KE of tank 2.
     

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